pinkink
pinkink
01-06-2018
Mathematics
contestada
algebra trig question need help asap number 18
Respuesta :
efawan
efawan
01-06-2018
Solution:
n=1,2,3,...,12
n=1, 2(1)+1=3
n=2, 2(2)+1=5
n=3, 2(3)+1=7
n=4, 2(4)+1=9
...
n=12, 2(12)+1=25
sum = 3+5+7+9+11+13+15+17+19+21+23+25
=168
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