Respuesta :

matthewwayoe22

Explanation:

[tex]poh = \frac{1}{2} \times pkb - \frac{1}{2} log(c) [/tex]

[tex]pkb = - log(kb) [/tex]

pkb = 3.066

C is concentration which is 0.24M

Substituting the values the pOH is

1.84.

pH +pOH = 14

pH = 14-1.84

pH= 12.16

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