9514 1404 393
Answer:
15
Step-by-step explanation:
Solving for x, we have ...
[tex]3x+\dfrac{2}{x}-4=2(x+9)-\left(7-\dfrac{1}{x}\right)\\\\3x+\dfrac{2}{x}-4=2x+18-7+\dfrac{1}{x}\\\\\boxed{x+\dfrac{1}{x}=15} \qquad\text{subtract $2x+\dfrac{1}{x}-4$}[/tex]
