Answer:
Solution given:
arcCD=2×35=70°[inscribed angle is half to the central angle]
r=10in
area of segment :[tex] \frac{70}{360} π×r²[/tex]
:[tex] \frac{70}{360} π×10²[/tex]
=[tex] \frac{175}{9} π[/tex] in²
C.[tex] \frac{175}{9} π[/tex] in² is a right answer.
