Answer:
[tex]V_2 = 0.0167L = 16.7 mL[/tex]
Explanation:
[tex]c_1 V_1 = c_2 V_2\\2.0 M \cdot 0.100L = 12M \cdot V_2\\V_2 = \frac{2.0M \cdot 0.100L}{12M} = 0.0167L = 16.7 mL[/tex]
