HazlynO132492 HazlynO132492
  • 03-11-2022
  • Mathematics
contestada

Y= x^4-2x^3-8x^2+12x-16

Respuesta :

IlaO702153 IlaO702153
  • 03-11-2022
[tex]Y=x^4-2x^3-8x^2+12x-16[/tex]

We will simplify further:

[tex]\begin{gathered} Y=x^4-2x^3-8x^2+12x-16 \\ when\colon x=0 \\ Y=0^4-2(0)^3-8(0^2+12(0)-16 \\ Y=-16 \\ \end{gathered}[/tex]

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