In this case you need to use the volume and temperature equation from Charles law.
[tex]\frac{V_1}{T_1}=\frac{V_2}{T_2}[/tex]
We are given T1 = 139 k
T2= 317 k
V2= 176 L
We want to find V1. Now lets re-arrange the equation.
[tex]V_1=\frac{V_2}{T_2}xT_1[/tex]
V1 = (176 x 139)/317
V1= 77.2 L
